Free energy with wires and magnets - can you come out ahead?

The basics of magnets and wires for free energy buffs.

Prepared by Tom Napier. Copyright 1998, All rights reserved.

 Over-unity motors and generators -- the bottom line

         Prepared by Tom Napier. Copyright 1999, All rights reserved.

   Some months ago I posted a detailed analysis of the forces between magnets and
current carrying wires.  (See "The basics of magnets and wires for free energy
buffs.")  For the benefit of those who found its 3400 words a bit much to wade
through here is the "executive summary."  See my earlier article if you want more

   Point 1.  Under ideal conditions the electrical power output generated when you
move a conductor through a magnetic field is exactly equal to the mechanical power
input needed to move the conductor.

   Point 2.  This applies to every microscopic piece of conductor, no matter in which
direction it moves, at what speed it moves or how strong the field is.

   Point 3.  The sum of the output electrical power round any closed loop is equal to
the sum of the input mechanical power, less any resistive losses in the conductor and
frictional losses in the moving parts.

   Point 4.  Thus the output power from a electrical generator of any type is always
less than the input power.  No external devices such as commutators, tuned circuits
or diodes can change this.

   Point 5.  Under ideal conditions the mechanical power output generated when you
pass a current through a conductor in a magnetic field is exactly equal to the
electrical power input applied.

   Point 6.  This applies to every microscopic piece of conductor, no matter in which
direction it moves, at what speed it moves or how strong the field is.

   Point 7.  The sum of the output mechanical power round any closed loop is equal to
the sum of the input electrical power, less any resistive losses in the conductor and
frictional losses in the moving parts.

  Point 8.  Thus the output power from a electric motor of any type is always less
than the input power.  No external devices such as commutators, tuned circuits or
diodes can change this.

   Point 9.  When you test a motor or a generator it can be very difficult to measure
both the mechanical and the electrical powers with sufficient accuracy to compute the
real efficiency.  The calculated efficiency may be either higher or lower than the
real figure.

  The bottom line: You don't have an over-unity system until you can demonstrate a
stand-alone device which drives itself and simultaneously generates a non-zero output

Machines which use magnets
Magnets are fascinating things, the way they push and pull and twist each other with no apparent connection between them.  It's tempting to suppose that there must be some way of arranging them to extract energy from them.  For example, one of the earliest perpetual motion machines proposed to use a lodestone, (a lump of naturally magnetic iron ore) to pull a ball up a slope towards a hole through which it would drop to cycle back to the start.  This didn't work.

Neither do its modern derivatives, and for the same reason.  Any work which a magnet does on an object has to be undone to get back to the starting position.  (This is also why an unbalanced wheel won't work.) Moving something in a closed loop in either a magnetic or a gravitational field causes it neither to gain or lose net energy.  Since this applies to all objects, it applies to every part of a machine, no matter how complicated it is.  There's no way of combining many zeros to get a positive result.

This doesn't stop people proposing motors which are driven only by magnetic fields.  These motors have rotors which are pushed or pulled most of the way around a circle by some arrangement of magnets.  There's nothing impossible about this, but the designers then expect the rotor to suddenly ignore the magnetic field and to complete the cycle.  This gets the rotor back to its starting point after delivering a net output of energy.  This is impossible.

Machines which use magnets and wires
So forget magnets acting alone.  Let's mix in some wires and electric currents.  Our whole civilization depends on devices which move wires in magnetic fields to generate electrical power and other devices which pass an electric current through a wire to generate motion; that is, on electrical generators and electric motors.

People are always asking me whether their odd configuration of wires and magnets will generate a power output from lesser input power.  The answer is no, but it is not always clear from elementary physics textbooks why this is so.  Textbooks are inclined to describe the forces involved without explaining what the implications are.

Generating voltages in wires
Let's start with generators.  If you have a uniform magnetic field, say between the poles of a horse-shoe magnet, and you move a straight wire through the field so that the field, the length of the wire and the direction of motion are all at right angles to each other then a voltage will appear between the ends of the wire.  In this simple case it is easy to calculate the voltage, it is equal to BvL volts. L is the length of the wire in meters, B is the strength of the field in webers/square-meter and v is the velocity of motion in meters/second.  To put this effect in perspective, 1 weber/square meter (10,000 Gauss) is a much stronger field than you can get from a small permanent magnet.  To generate a field this strong and a meter across would require an electromagnet weighing several tons.  Wiggling a few inches of wire in the field of a small magnet will produce a few millivolts.  It makes no difference whether it is the conductor or the field which is moving, only the relative motion counts.

Looking at this effect in isolation, we have a length of wire moving continuously in a uniform field.  No work is needed to keep the wire moving since, once we have started it off, it is generating no electrical power output.  It took some energy to overcome the wire's inertia when we started it moving and some more energy to establish the initial field between the ends of the wire but we will overlook them.  (When the wire stops moving we can, in principle, recover that energy.)

Completing the loop
Suppose we want either to measure the voltage generated or to do something useful with it.  To attach a voltmeter or a load resistance we must complete a loop which contains the bit of wire we are looking at. Suppose we truly have a uniform field and that it is very large, at least in the direction we are moving.  Imagine, for example, that we are traveling north on rails between the poles of a magnet which is several miles wide.  Our test wire extends from east to west and the field goes from down to up.  We are traveling fast enough to generate one volt between the ends of the wire.

To make it easy, we are sitting at the east end of the wire so we can hook up our voltmeter up to the east end without any trouble.  How do we connect the voltmeter to the west end of the wire?  With another wire, of course.  But that wire is also going from east to west and is traveling at the same velocity as the first one.  It also has a voltage of one volt induced in it.  The west end of both wires have the same voltage on them; when we connect them together the net voltage around the circuit is zero and that is what our voltmeter will show.  No matter what route the second wire takes from east to west it will have exactly the same voltage across it as the test wire.  If we connect a load resistor to the loop of wire no current will flow and no output power will be generated.

What this shows is that in order to generate a voltage in a loop of wire one of two conditions must hold.  1) the field in one part of the loop must be different from the field in another part or, 2) the velocity of one part of the loop must be different from the velocity of another part of the loop.

Types of loops
The first condition can be met, for example, by using a small magnet and a large loop so that only a part of the loop is in the strong field.
Obviously this limits the length of time we can generate a voltage at any given velocity.

One way to meet the second condition would be to slide the wire through the field on rails.  Since the rails would not be moving they would not contribute to the voltage.

These illustrate a general principle which says that so long as the product of a magnetic field and the area of a loop remains constant no
voltage is generated round the loop.  Either the area of the loop or the strength of the field must change to generate a voltage.  You can vary the strength of the field within the loop by moving the loop from a weak field to a strong field, that was Case 1 above, or by changing the effective area of the loop, as in Case 2 above.

  Another way to vary the effective area of a loop is to rotate it in the field.  This makes its effective area go from +A to -A and back to +A every complete turn.  Or look at it this way, twice per turn one side of the loop will, briefly, be moving in the opposite direction to the other. It will generate a voltage which adds to the first side's voltage rather than subtracting.  Half a turn later the loop will be generating a voltage in the opposite sense.  Thus, if we hook up the two ends of the loop to slip rings we will see an output voltage which alternates as the loop turns.  Not only can we measure the voltage but we can get a useful output. We have just invented the alternator.

If the two ends of the loop are connected to a split ring around the shaft then a brush on each side of the ring will pick up pulses of voltage which all have the same polarity.  By adding loops, each at a slightly different angle, and connecting each to a pair of segments on a commutator, at any moment the brushes will connect only to the loop which is moving fastest in the field.  This gives an almost steady output voltage, resulting in a DC generator.

What happens elsewhere in the loop?
Let's go back to that original piece of wire.  If it is not at right angles to the field or if it is not moving at right angles to its length the voltage generated will be less than in the right angle case.  It will be proportional to the sines of the angle between the motion and the field and the sine of the angle between the wire and its direction of motion.  If the motion is along the field or the wire is moving lengthwise no voltage will be generated.

By using this relationship we can, at least in theory, calculate the voltage round any loop of wire moving at any velocity in any magnetic field by adding up the contributions from each little piece of wire.  Some quite ingenious ideas fall flat when this is done.  The inventors have looked only at the interesting part of their machine and have ignored the fact
that all magnetic fields loop back on themselves somewhere.  The voltage generated in that part of the loop also has to be taken into account.  It often cancels out the voltage in the rest of the system.

Where does energy come in?
As I mentioned, moving a wire through a field requires no energy.  That rotor I mentioned will spin until friction stops it.  (I know, I'm ignoring eddy current losses here.)  You can hang a voltmeter on the output and measure the voltage without any significant effect.  By giving the loop of wire many turns you can generate as big an output voltage as you please. Using a stronger field, a faster rotor speed or a longer rotor also increases the output voltage.  Unless some current flows no energy is needed to keep things moving.

What happens when current flows?
Let's just stop there and look at another phenomenon which occurs when you play with wires and magnets.  This time let's hold that wire in the uniform field in a fixed position and pass a current through it.  What happens is that the wire tries to move in a direction at right angles to both the field and the current.  The force needed to keep the wire still is given by ilB where i is the current in amps, l is the length of the wire in meters and B is the field strength in webers per square meter.  The force is measured in Newtons.

If we let the wire go it will start moving across the field.  Its acceleration will be proportional to the current times the field strength. In Newtonian physics there is no limit to how fast it will go.  (This principle has been proposed for firing payloads into space.)  However, when the wire moves a voltage is generated across its ends.  This is where we came in.  The faster the wire moves the higher the voltage generated.  This voltage acts in the opposite direction to the current we are feeding in, making it harder and harder to force that current through the wire.  For a given current, low speed equals low back voltage and hence low electrical power input.  A high speed generates a high back voltage and thus requires a high electrical input power.  Now the mechanical energy out is simply equal to the force exerted times the speed.  Low speed equals low output power and high speed equals high output power.  Are you beginning to see a pattern?  Low mechanical power out equals low electrical power in; high mechanical power out equals high electrical power in.

Computing the input and output powers
The power in watts which we are feeding into the wire is the product of the current and the voltage.  If the wire is moving at a constant velocity and is lifting a weight at so many meters per second.   Then the mechanical power being generated is just the product of the velocity times the force on the wire.  The force is proportional to the current and the back voltage is proportional to the velocity so the input power is proportional to the output power.  When you trouble to multiply out all the units it turns out that the mechanical power out is exactly equal to the electrical power in.  (With the usual provisos about friction and resistive losses being negligible.)

Turn things around
Exactly the same thing applies the other way round when you apply mechanical power to a wire.  As the wire moves it generates a voltage proportional to its velocity.  If a current flows the electrical output power is proportional to the product of the voltage and the current, that is, it is proportional to the product of the current and the velocity.  Now when a current flows in the wire it generates a force on the wire. Surprise, surprise, this force acts to oppose the motion of the wire.  To keep it moving you have to push it harder.  The mechanical energy you must apply is proportional to the velocity and the reverse force caused by the output current.  In this case the output electrical power is equal to the
input mechanical power.

 In a way this is rather wonderful.  It means that we can convert mechanical power into electrical power or electrical power into mechanical power with practically no losses.  This is impractical with thermal power.

Unfortunately, since the equality of power in and power out applies to each little piece of wire, no matter how it is moving and in whatever magnetic field, you can never come out ahead.  Any device, no matter how ingenious, which generates an output current also generates a force opposing its motion.  Any device which generates motion from a current also
generates a back voltage which opposes the input current.

A practical case
The alternator I described will spin happily with almost no input power until you connect something to its output terminals.  Then a current will flow which is given by the output voltage divided by the total resistance of the wire loop plus the resistance the load you apply.  If the loop resistance is not zero the output voltage will drop.  The useful output power is this lower voltage times the current so it pays to use low resistance wire.

By allowing a current to pass you are applying a mechanical load to the alternator.  It thus requires more input power to keep it turning.  The more output power you take the more difficult it becomes to turn the rotor. I have a DC motor with a built-in reduction gearbox.  It is easy to turn its output shaft by hand when its leads are open circuit but almost impossible to turn it if they are shorted together.  Power out, at best, equals power in.

What about the homopolar generator?
Sometimes it can be quite hard to see just where the current loop is. Faraday discovered that if you turn a conducting disk in a magnetic field you can measure a voltage between the shaft of the disk and its rim.  This device, the homopolar generator and its equivalent, the homopolar motorhave been baffling people ever since.

Consider a disk which is rotating in a uniform magnetic field.  The field passes through the disk at right angles to its surface.  Any radius of that disk is moving through the field.  The parts of the radius near the shaft are moving slowly and the parts near the rim are moving quickly but they are all moving in the same direction so the voltages generates by each little bit of the radius all add up.  The result is a voltage all round the rim of the disk which is higher than the voltage at the center.

If you mount a sliding contact at any point on the rim you can measure this voltage.  It won't be a large voltage since only a single conductor is moving through the field and parts of it are not moving at the full speed. Suppose you had a copper disk 20 cm (8") in diameter, turning at 10,000 revolutions per minute, and that you could put it in a uniform 0.1 weber field.  (This would be a very dangerous thing to try!)  The rim will be moving at 105 m/s so the mean velocity of a radius is half that.  The length of the radius is 0.1 meters and the field is 0.1 webers so the voltage will be 0.52 Volts, about a third of what you'd get from an alkaline cell!

If your disk had a low resistance, and if the brush contact and the external circuit also had a low resistance, then quite a substantial current would flow from the shaft to the rim.  Because the voltage is generated on all radii of the disk you could put brushes all round the rim and reduce the effective generator resistance.  Unfortunately the frictional forces on the edge of the rim chew up a lot of input power.  As in any other generator, the motion of the disk is resisted by the force which the magnetic field exerts on the output current.  Thus homopolar generators are only useful if you need a high current at a low voltage and don't care how much energy it takes to turn the disk.

As a footnote, I mentioned using a uniform magnetic field.  You might think that having a field just between the shaft and the point on the rim where the brush is placed would be more efficient.  Unfortunately, when the field is not uniform over the whole disk local currents are generated in the disk, heating it up and wasting input power.  This "eddy-current" effect is the basis of the magnetic brake.  Electricity meters are one common application and some car speedometers also depend on this effect.

The homopolar motor
If you pump a huge current into the disk the magnetic field will generate enough force on it to make it rotate despite the brush friction. (Early experimenters made contact to the rim of the disk by making it pass through pools of mercury.  Since mercury vapor is rather poisonous this is not done any more.) Unfortunately, generating large direct currents at low voltages is a notoriously inefficient process.  AC can be transformed down to get a low voltage but the rectifying device needed to convert the output to DC tends to drop about half a volt, making the efficiency less than 50% before you start moving anything.  About the only device which can generate large currents at low voltages at all efficiently is, you guessed it, a homopolar generator.

Defeating your own object
One hopeful inventor thought that you could generate an output voltage without generating a reverse force by attaching the magnets generating the field to the rotating disk.  Unfortunately, this doesn't work.  Only relative motion of the field and the current carrying disk generates a voltage.  What misled this inventor was that he did measure a voltage when he connected a meter between the shaft and the rim of the disk.  He hadn't realized that the ring magnets were generating two fields, one in the disk between the magnets and another toroidal field in the space around the disk.  The disk wasn't generating a voltage but the wire leading to the meter was being cut by this rotating field and was generating a small voltage.  Connecting a current meter would have shown an output current. However, this current would have reacted on the rotating field to slow the disk down.  As I said before, you have to consider what is happening
everywhere in the system, not just focus on one part of it and ignore the rest.

The effect was the same as if the disk and magnets were stationary and a contact had been spun round the edge of the disk.  The wire going to the contact would have been moving in a magnetic field and all the usual rules would apply.

No arrangement of wires and magnetic fields and moving parts is going to generate more electrical power than the input mechanical power or generate more mechanical power than the input electrical power.  If you want to experiment, by all means have fun, but please don't think you are going to bring about an energy revolution.  Above all, spend only your own money, not other people's unless you want to spend the rest of your life dodging irate investors.

Additional notes by Eric:
A perpetual motion of new "inventors" thinks they are making fresh attempts at this "engineering holy grail".  I've had scores of people tell me that they are hoping to fine tune some collection of wires and magnets that can finally come out ahead.  Justifications are given along the lines, "if I try hard enough"  "it must be possible because it is needed", "xyz book reports someone did it and then forgot how", or "my new theory of physics explains why it can work".  My prize money for proof of free energy will be awarded if anyone can show me the real thing working - and I have no interest in someone's new theory until they win the prize.  I feel the existing formulas comprising relationships between energy, motion, current, magnet flux lines, fields, etc. do a fine job of explaining evidence.

What about systems involving batteries?
Putting an occasional back surge of voltage in a battery can help get a temporary increase of performance. Also, most batteries after being discharged and disconnected can revive a little on their own. FE claims involving batteries never are operated indefinitely which would show if they are just running down the batteries. Most demonstrations I know of (like the farces Joe Newman puts on) involve pathetic means of comparing input and output energy levels.  Motors/generators with big sparks are only wasting excess energy and likely creating illegal noise on radio frequency bands.


Free Energy FAQ page
Joe Newman's nutty claims.
History of free energy claims
Eric's discussion of real forms of free energy
 great discussion of entropy
Eric's history of Perpetual Motion and Free Energy Machines
 Joe Newman's Free Energy Claims - are they valid?
 Free Energy FAQ page
 Eric's Page examining Dennis Lee's amazing claims of Better World Technology
 Tom Bearden’s MEG device A rational review of meg claims  and Randi’s info and my info

. free energy scams   Tback to Eric's main Dennis Lee page    what about Joe Newman? Also, Amin, Mills (who may be legit?) Tilley, Perendev, Bearden Lutec and Tewari Xogen and GWE Adams

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 PhACT-FAQ on Heat Based Free Energy Prepared by Tom Napier

Things you won't learn at a free energy seminar.

   Prepared by Tom Napier. Copyright 1999, All rights reserved.

   You would expect that anyone promoting a machine to generate free
energy would be an expert on the subject of energy and its measurement.
After all, if you can't measure energy input and output accurately how can
you tell that the output exceeds the input?  Of course there is a simple
answer to that.  Connect the output of the machine to its input and
demonstrate that it runs continuously while generating significant excess
power.  Failing this test, which no free energy machine has yet been seen
to pass, you must rely on measurements of input and output power.  You
must also know how to compare them.

   Well, if there is one thing which free energy promoters seem to have in
common it is a massive ignorance, real or feigned, about what energy is
and how to measure it.  Luckily for them, their audiences seem to share
this failing and thus cannot readily distinguish between the plausible and
the possible.  To remedy this lack, this note attempts to summarize the
basics of energy in two thousand words or so.

What is energy?

   "Energy" is a general concept which scientists and engineers use to
make their sums come out right.  Energy comes in many different forms,
light, heat, mechanical motion and electricity are all forms of energy but
these can all be measured in the same units.  When you change one form of
energy into another you always end up with exactly as much as you started
with, if you have accounted correctly for all the inputs and outputs.
This is such a basic idea that it is given a name, the Conservation of
Energy.  It is the most fundamental of the scientific laws.  By the way,
it is a generalization from observation, not something which spoil-sport
scientists just made up because they liked it.

   In practice, when you convert energy from one form to another some of
it is invariably converted into an undesired form such as frictional heat.
This subtracts from the useful output energy.  Thus the useful output of a
conversion device always contains a bit less energy than its input.  This
is expressed in the form of an efficiency, (Useful output)/(Necessary
input).  Since useful energy is always lost the efficiency is always less
than one.

   We are used to the idea that scientists and engineers are making
constant improvements in things and efficiencies are always rising.  Is
there a limit to efficiency?  After all, the idea behind one type of free
energy machine is that one can make the efficiency greater than one, hence
the name "over-unity" applied to such devices.

   An over-unity machine would require an input of energy in some form to
make it run but it would generate more energy, in the same or a different
form, than it consumes.  As mentioned above, the simple way to prove that
a device is "over-unity" is to run it from its own output.  No matter how
many calculations you may be shown to "prove" that a machine is over-
unity, if it can't pass that test then it isn't.

Mechanical energy

   Let's define a few terms without getting too technical.  Force should
be a familiar concept.  A push from a spring is a force and so is the
weight of an object.  However, until the thing to which the force is
applied actually moves, no work is done.  You may think you are working
hard when you hold a weight up in the air but you aren't really.  You
could be replaced by a shelf which does no work at all.  When you lifted
the weight off the floor you did do work.  You exerted a force for a
distance and that is the definition of "work," Force times Distance.  In
this case the work, or energy, would be measured in foot.pounds.

   Because you lifted it, the weight has acquired energy which it didn't
have when it was on the floor.  You could get this energy back again by
letting the weight fall, for example by connecting a string to the weight
and letting it drive an electric generator.  (Of course you could just let
the weight fall.  Then its energy will go into making a hole in the

   No amount of push represents energy unless the thing being pushed
moves.  One demonstration you might see is a car engine bending a torque
wrench.  Torque is just a force which tends to make something turn.  It is
measured by multiplying the force by the distance from the pivot.  Funnily
enough this also gives foot.pounds but this doesn't mean that torque
equals energy unless the thing the torque is applied to moves.  If the
shaft made a complete turn then the torque would have been exerted through
2 pi radians.  The work done would have been equal to 2 pi times the


   Power is simply the rate of doing work, that is, it is work done per
second.  A one horsepower motor outputs 550 foot.pounds per second.  That
is, it could lift a 550 pound weight at one foot per second or a 50 pound
weight at 11 feet per second.

   One way of measuring the 1 HP output would be to apply a brake to slow
the motor down.  This is wasteful, all the motor output is converted to
heat, but it allows you to measure the motor's output at any speed you
want.  The torque exerted on the brake can be multiplied by 2 pi times the
rotation rate to calculate the output power.  For example, suppose the
motor was rated at 1 HP at 3000 rpm.  If you braked it to run at 3000 rpm
then in each minute it should generate an output of 550 times 60
foot.pounds.  At 3000 rpm this is 11 foot.pounds per turn, corresponding
to a torque of 11 divided by 2 pi or about 1.75 foot.pounds.  If you
measured the force on the brake at one foot from the motor shaft it should
be 1.75 pounds if the motor is performing as planned.

   Normal electric motors become very inefficient if you brake them so
that they run much slower than the makers intended.  When running at their
normal speed, motors are from 75% to 90% efficient.  If you hear of a
device which doubles the output of an electric motor this doesn't mean
that it has gone from 80% to 160%.  It is much more likely to have gone
from 10% to 20%.

   Mechanical energy is commonly measured in the foot.pounds used above
and mechanical power in foot.pounds per second or, with the 550 conversion
factor, in horsepower.  (This is all much simpler in the metric system.)
Since many over-unity systems use electric power either as an input or an
output we need to be able to measure electrical power and to compare it to
mechanical power.

Electrical power

   Since we usually encounter electricity in the form of a current which
supplies continuous power it is much more common to refer to electrical
power than to electrical energy.  Thus we talk of watts or kilowatts, the
units of power.  In mechanics our basic energy unit, the foot.pound, was
divided by time to get the rate of power usage.  In electricity we
multiply power by time to get total energy.  Thus the electric company
bills you for your energy usage in kilowatt.hours.

   Two things need to be considered next.  How to convert from electrical
measurements to mechanical measurements and how to measure electrical
power.  Let's take the easy one first.  If you compare the units in which
electrical and mechanical power are measured you find that one horsepower
is 0.7457 kilowatts.  One outcome of this is that if you had an over-unity
electric motor it would drive that brake I mentioned at a 1 HP output
level using less than 0.7457 kilowatts of input.  If the motor is 85%
efficient, a typical figure, it will actually take 0.7457/0.85 or 0.877
kilowatts to drive it.

Measuring electrical power

   Measuring electrical power is very easy in principle and very difficult
in practice.  If the current and voltage going to a device never change
than the power input is simply current times voltage.  Both can be easily
measured with an accuracy of a percent or so.  Unfortunately, while supply
voltages, as from a battery, can be almost constant, currents vary rapidly
with time, particularly when you are driving a motor.  Most current meters
measure the mean value of the current.  This will only tell you the mean
power if the voltage is absolutely steady.

   If the voltage changes when the current changes, which it almost
certainly does, then measuring the mean current gives quite the wrong
value for the power.  What you have to do is to use a wattmeter.  This
multiplies the instantaneous voltage by the instantaneous current to get
the power and then averages the power to arrive at the mean value.
However, even accurate wattmeters can give spurious results if the current
contains very fast spikes.  The current into electric motors often does.

   Things get much more complicated when the power source is alternating
current (AC).  Then, even if the mean current and voltage are absolutely
constant the power can be changing.

   There are two ways of measuring AC voltages and currents.  Cheap meters
assume that the AC voltage is always a pure sine wave.  They turn it into
half cycles all in the same direction and measure the mean value.  Then
they apply a correction factor to convert this into a true voltage.  Since
the AC voltage is rarely a pure sine wave and AC current almost never is,
cheap meters are unreliable even when measuring voltage, much less power.
They only give reliable results if the load you are connected to is a pure
resistor such as an electric heater.

   The alternative is to use an RMS meter.  (Root Mean Square, it's a
description of the averaging method they use.)  This will give a correct
voltage or current reading unless there are spikes in the current.

   There are two standard ways of measuring current.  One is to pass the
current through a small resistor and to measure the voltage.  This is
potentially accurate but is prone to error in practice since the voltage
measured is usually in the millivolt range.  It is easy to pick up
interference or to include more resistance in the circuit than you mean
to.  The alternative is the "clip-on" ammeter.  This can also pick up
interference and may not be better than 5% accurate anyway.  Not all clip-
on meters can measure DC.

The power factor problem

   Even accurate RMS voltage and current meters cannot measure power input
or output.  This is because of the so-called Power Factor (PF) of the
source or the load.  The PF is the ratio between the real power and the
product of the current and voltage.  It is the cosine of the phase angle
between the AC voltage and the AC current.  Luckily the true power is
never greater than the product of the RMS current and voltage so current
and voltage measurements give an upper limit to the input power of a
device.  They should not be used to measure the output power.

   The PF of a device can range from one down to zero.  Resistors have a
PF of one but pure capacitors and inductors have a PF of zero.  Most real
devices are designed to have PFs close to one but the real power input or
output of a device can be close to zero even when input large currents are

   To take a dangerous example, if you connected a big capacitor to a 110
V outlet a huge current would flow through it but your electricity meter,
which measures watts quite accurately, wouldn't register any power drain.
Unfortunately the current flowing through the wires leading to your house
would make them heat up so the power company would be supplying power
which no one would be billed for.  They don't like doing this which is why
they are likely to disconnect you if you try this experiment.

   Electric motors are quite inductive and show a similar effect.  This is
why large electric motors are fitted with capacitors.  These stop them
taking more current than their power rating would indicate.

   Thus to measure the output power of a device you must use a meter which
takes the power factor into account or which uses the same instantaneous
multiplication process mentioned above for DC power measurements.

The last resort

   Luckily there is a way of measuring electrical output power which
cannot be fooled.  If you drive a resistive load the rate of heat output
is an accurate measurement of the electrical input power.  Some RMS meters
actually measure the heat generated by the input power.  A good way of
measuring the output of an over-unity device is to connect it to an
electric kettle containing a known amount of water.  If the room
temperature is known, and the kettle is well wrapped in insulation, the
time it takes to bring the water to the boil will indicate the true power
output.  Just don't bank on any inventor letting you run this test!


   I hope this note goes some way to showing that there is scope for error
even in apparently simple input and output measurements.  If any device
were really "over-unity" it would be easy to connect its output to its
input.  There's a good reason why that demonstration is never shown, it's
too hard to fake.

The following are usefull power measurement ideas from David:


Paul MacDonald <> wrote:

>A better way is to measure the voltage drop across a resistor.  Man, if you
>took a repair course, you would have been soundly scolded.  A clever term for
>this is "fault finding by smoke" another term that almost applies is
>"crowbarring" (where you put some tin foil over a blown fuse).

Agreed.  A shunt resister is the way to go in these cases.  Use a low-resistance,
precision resistor and measure the voltage drop across it with a millivolt
meter.  In DC circuitry you can get really accurate results if you're careful
with your calibration.

It's a whole different ball game with AC circuitry.  Phase differences between
the voltage across the device and current through the device make power
measurement tricky, to say the least.  This is why RLC circuitry shows up
so often in free energy devices.  The experimenter usually uses standard
AC voltmeters and ammeters which are fooled by non-sinusoidal waveforms.  Many
of the off-the-shelf meters are even fooled by non-unit power factor (cosine
of the voltage-current phase difference).  Measure the electrical input power
into the device with one of these off-the-shelf meters and you get a very low
number.  Compare it to the output power (shaft, chemical, etc.) and you have
what looks like free energy.  Add a DC offset to the AC signals and virtually
any off-the-shelf meter is screwed.  (Dennis Lee makes great use of this
error in his traveling road show.)

When you get right down to it, the best way to measure power into or out of
a device using RLC circuitry is to use a shunt resistor on one of the leads
and to measure the voltage drops across the resistor and across the device.
A high-speed data acquisition system with simultaneous sampling of the two
voltages is a must.  And the acquisition rate must be at least twice the
frequency of the highest harmonic you hope to resolve.  Low-pass filtering
will help eliminate aliasing of frequencies above the Nyquist.

The shunt resistor voltage record is then translated into a current record.
Then for each instant in time, the corresponding voltage and current values
are multiplied to calculate an instantaneous power value.  This "power
waveform" is then integrated with respect to time.

National Instruments makes a data acquisition card for the PC that will sample
four channels simultaneously at 12 bits and 5 MHz/channel, for a mere $3000.
They've got some less expensive ones, but they don't sample simultaneously.