Text: Subject: Re: [asc2k] colour and sound and octaves Date: Thu, 29 Mar 2001 09:06:29 +0200 From: Wouter Hagens To: CC: David Wilcock Dale, Thank you very much for your fast and helpful answer! I just give you my way of using the data. If you have additional comments or suggestions please let me know. >From literature I found that in the visible spectrum:  red 780-640 nm  orange 640-595 nm  yellow 595-570 nm  green 570-500 nm  blue 500-450 nm  violet 450-380 nm in frequencies (Hz) this is  red 3,85E+14 4,69E+14  orange 4,69E+14 5,04E+14  yellow 5,04E+14 5,26E+14  green 5,26E+14 6,00E+14  blue 6,00E+14 6,67E+14  violet 6,67E+14 7,89E+14 Using your data and going down in octaves I come to note Hz this times gives Hz and equals nm D 288 2^41 6,333E+14 474 E 324 2^41 7,125E+14 421 F 341 2^41 7,504E+14 400 G 384 2^40 4,222E+14 711 A 432 2^40 4,750E+14 632 B 486 2^40 5,344E+14 561 C 512 2^40 5,629E+14 533 By copy: David, you mentioned in your table in chapt.02 for F 360 Hz, B 480 Hz and C 540 Hz. In my opinion it is better to take the values as in the table above, taking into account the factor 1,059463 between half tones starting from A4=432Hz. Using the above spectra range-data or the spectrum image as attached, I find: Wouter Dale David Cousto D=Do blue orange red light blue E=Re indigo yellow orange violet F=Mi violet green yellow violet red G=Fa red blue green orange red A=So orange indigo blue orange yellow B-La yellow violet indigo yellow green C=Ti green red violet green As you say there are many frequencies from one note to the next and there is no exact and only frequency for any given colour. This is also only from pure physics point of view. The visible spectral range is so small. Further I know that it is possible to determine the relationship with radiesthesia using the virtual cone pendulum; I am investigating that. Best regards, Wouter

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