RE: Question about the aether

Carrigan, Ken ( (no email) )
Wed, 5 Apr 2000 13:28:05 -0400

Peter,
The forces are correct and help it rotate. Remember that the center
of the axle is common relative to the outer rim(s). There are
two 180 degree takeoff points where the current (or charge) is
taken from the center of the disk (axle) to the outer rim and
run in opposing directions. Electromotance is dependant on
these paths (separate each) and each contributes to the integral
of (u X B)dl. Funny but there are different ways to look at this
in reference to the observer whether on the disk or external to it.
The 'laboratory' observer says that the magnetic field is static
but the magnetic force (u X B) on the 'free charges' in the moving
conductor produces the electromotance. The 'disk' observer says
that the conductor is at rest but that it is in a time dependant
magnetic field.

Anyway the Force vector (u X B) for each contact side is on the
rim of the disk rotating about the axis lying on its plane and
perpendicular to the uniform magnetic field B. The vector 'u'
is also perpendicular to the plane of the disk. This then would
produce a rotational force - hence Homopolar generator.

The error I made was that the force is not "out of the disk
and perpendicular to the axis" but rather on the rim, perpendicular
to current flow, and perpendicular to magnetic field B. They
actually add together. If one was to force current the other
way the disk would turn, as a Homopolar motor would operate.

v/r Ken Carrigan

-----Original Message-----
From: Peter Ammon [mailto:pa44@cornell.edu]
Sent: Wednesday, April 05, 2000 11:53 AM
To: interact@keelynet.com
Cc: kcarrigan@anteon.com
Subject: RE: Question about the aether

>
>What I could use is some help in proofing the equations that addresses
>the Faraday generator which could maybe be made to produce overunity
>if the equations proof out. In my field I first like to make up
>a hypothesis and then conduct experiments around that. My web
>site (1997) never was finished and left it with some errors in
>relating kinetic energy to potential energy. I might add gross
>errors? 95,000% overunity? <g> However, if someone can complete
>the equations and address friction energy loss and relate it
>to normal operational parameters, then maybe this generator can
>be built. One can build many many many Faraday generators and
>not get overunity, why not look at the physical laws first and
>see if there is potential in allowing 'free energy'.
>http://www.geocities.com/CapeCanaveral/Hangar/5307/Principles.htm

Hi Ken! I read your article, and I believe that you made a mistake when
calculating the direction of the force via the Biot-Savart law. Let's draw
a disk on a piece of paper rotating counterclockwise with the magnetic
field coming out of the paper. Examining the top of the disk, the velocity
of the particles is left and the magnetic field is out, so by the right
hand rule, the force on a positive particle is up, and therefore so is the
current. Applying the Biot Savart law with the right hand rule again on
the top of the disk, we see that if the current is up and the magnetic
field is out of the paper, then the force on the disk will be to the right,
not out of the paper as your article claims. In other words, the magnetic
field will exert a force on the disk that is tangent to the disk and in the
opposite direction from the rotation. Therefore, the two brushes cannot be
used to cancel out the force, because they will exert the torque in the
same direction on the disk.

This jives with conservation of energy; if the disk rotates through a
magnetic field, then it makes current, and that energy has got to come from
somewhere, so it comes from the angular kinetic energy of the disk.

Let me know if you have any questions or disagreements about this flaw.
Good luck on any future theories.

-Peter

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