Really? You are saying that if the speed and the wavelength changes the
frequency remains the same? Fancy that. Correct me if I'm wrong and
please give URLs or definitions to back it up but;
To my understanding a wave consists of two parts, a pressure side which
we normally call 'positive' and a suction side which we call 'negative'.
If we take a fixed point such as a pole sticking up in a body of water
and we slap the water once, it will create a series of waves which will
pass that pole
As the waves radiate away from the source, they lose energy as they
propagate outward over larger areas and dissipates until the waves
achieve equilibrium with the rest of the body.
Is that in error?
So we have agreed on what a wave is?
-----------------------
If we count the number of positive OR negative portions of the wave that
pass that pole in a given time period, say how many per second, we have
the frequency.
Is that in error?
So we have established what frequency is, is that agreed?
A dictionary definition of frequency;
http://www.dictionary.com/cgi-bin/dict.pl?term=frequency
frequency n 1: the number of occurrences within a given time period
(usually 1 second); "the frequency of modulation was 40
cycles per second"
[syn: frequence, oftenness]
-----------------------
Each wave has a specific length, thus the wavelength.
The frequency is how many of these waves pass a fixed point per second
(or minute or whatever temporal measurement you desire).
Is that in error?
So if you make the wavelength longer, you lower the frequency by
necessity.
The shorter the wavelength, the higher the frequency.
The longer the wavelength, the lower the frequency.
Is that in error?
Since frequency is the number of wavelengths that pass a fixed point,
then if you speed up the number of wavelengths that pass that point per
second, would not the frequency change since you have more waves passing
the point per second?
Is that in error?
I rest my case..<g>...
Slavek Krepelka wrote:
>
> Jerry W. Decker wrote:
> > Now if those lines are representing the zero crossing point of a wave,
> > then that means the waves are getting closer together which means higher
> > frequencies while it is traversing the medium of the diamond (or
> > anything denser than vacuum).
>
> Wrong Jerry, The frequency is the same. It is the speed and the wavelength
> which changes.
>
-- Jerry Wayne Decker / jdecker@keelynet.com http://keelynet.com / from an Art to a Science Voice : (214) 324-8741 / FAX : (214) 324-3501KeelyNet - PO BOX 870716 - Mesquite - Republic of Texas - 75187------------------------------------------------------------- To leave this list, email <listserver@keelynet.com> with the body text: leave Interact list archives and on line subscription forms are at http://keelynet.com/interact/ -------------------------------------------------------------