Re: Magnetic Mercury Power

Jerry Wayne Decker ( jwdatwork@yahoo.com )
Thu, 1 Oct 1998 15:23:48 -0700 (PDT)

Hi Ken et al!

That's what I was questioning, how such a high current could be
produced to lift any appreciable weight.

Not to mention that the coil must be arranged so that the DC produced
North on one side and South on the opposite side, then spin the thing
to establish the stability of angular velocity as in the spinning
Levitron magnetic tops.

---Ken Carrigan wrote:
>
> Just thought that I would interject here.. that this levitating of a
> metalic object is not easily done. It requires lots and lots of
current.
>
> For ex:
> The current density in a wire to levitate it at the earths
equator..say
> 1 x 10-6 Telsa, and copper being 8.9g/cm3.
> This would require 872amps/cm2!
> Now figure copper's resistivity at 1.7 x 10-8 ohm * m, I'll leave it
up
> to you all to figure if this is practicle or even possible.
>
> Do you really think, that you could produce a flying device that could
> generate enough current density (remembering added weight of
> non current carrying wire) to carry it 1" off the ground?
>
> Personally.. I don't believe this can be could be achieved in a self
> contained environment...i.e... without some external umbilical cord
> attached.
>
> v/r Ken Carrigan
>
>
>
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