I do not believe in relativistic electrodynamics but aetheric
electrodynamics,
this is just showing that relativistic electrodynamics does have FE as a
conclusion!
The first is that relativistic electrodynamics has an FE loop hole,
Because
the magnetic field around a particle is relative to the velocity of the
observer to the particle, the particle does not 'see' any magnetic field
from any charged particles in the same frame including it's own, So an
electron accelerating does not see or feel it's own magnetic field as it
does not have one in that frame, It only sees or feels fields from
charges
that it has a relative motion to, Now I set that all out so you know but
that is in fact not a necessarily fact for this effect, Now if you have
a
number of stationary charges (lets say negative) and an accelerating
charge of the same sign it will feel a field from the stationary
electrons
and as the electron is accelerating the field will be seen to expand and
the induced electric field will further accelerate the electron, you see
a
moving electric field creates a magnetic field and a moving magnetic
field
creates a electric field, the electric field the charged particle will
feel will accelerate it, this is how self induction works in
conventional
relativistic electrodynamics, the electrons in the wire do not feel
their
own magnetic field because they feel the field of the protons in the
wire
as there are more positive stationary charges than negative ones because
a
number of the electrons are moving with the stream so the stream does
not
feel it's own fields as there is no relative motion between them, now in
the first case the charges were accelerating relative to other charges
of
the same sign, but this time the sign of the accelerating charge is
opposite to the (majority of the) stationary charges so the induced
field
retards the acceleration but when the electrons decelerate the magnetic
field is collapsing not expanding so the induced electric field helps
the
electrons keep moving, It is true in the first case though (with the
same
sign) that the charges when decelerating will only be aided in that
deceleration so some wave shapes would have you lose as much (or more)
energy as you took out in the first case but others will be decidedly FE
because only the slightest energy is needed to accelerate the electrons
(and once stared it will continue with no more energy until the losses
are
too high for the acceleration or current increase to continue) as the
induction is now positive which means you take before you gives, you
invested no energy in so what you pay back so to speak is totally your
choice.
Note: If you are not sure of any point above I know that it is all
totally
conventional, anyone with good knowledge of electrodynamics should
be able to agree (except the FE part which I am sure they will deny as
it is their way ;)
I can't be bothered giving the others errors in relativity now, they are
just
simple logical flaws in relativity (they really are simple but I
guarantee they
are correct I am not ignorant of relativity).
John Berry