Re: Electrostatic Power Generating System

Ken Carrigan ( (no email) )
Sat, 13 Mar 1999 15:45:09 -0500

This is a multi-part message in MIME format.

------=_NextPart_000_002B_01BE6D68.79D9DD20
Content-Type: text/plain;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable

Electrostatic implies that no power is needed to sustain the field, when =
in fact there
are losses to keeping any high potential in free space. Now if one =
tries to use this
electrostatic energy for work, then the field will start to either =
deplete or require more
current to sustain itself. In other words... the field is NOT free. =20

What we should be looking at HARD, is an energy supply that is NEVER =
depleted.
One that if we try to use the field supply, it would allow us to use it =
without depleting.
Like an endless river supply. PERMENATE MAGNETICS!! Free B-Field!! =
This is
our key to endless energy, but we have to get the static magnetic field =
to become
oscillatory. If you can make a magnetic field from a permenate magnetic =
oscillate
by either machanical means or field modulation means, there would be =
your answer.
Now, this mechanical or field modulation (FM) means would also have to =
be free..
or at least the magnetic field oscillations (integrate for power =
extraction) would have
to supply the oscillations means. =20

Any takers for this kinda project? The TOMI is close..where magnetics =
are used to=20
rotate a ball bearing. If one could produce that...ball bearing =
rotating continually..
I'd have to say.. you would be 75% there to answers to free energy.

v/r Ken Carrigan

PS... it also could be that high frequency oscillations are the answer =
vice slower or
lower oscillations. Something like a car.. for gas milage? Too fast =
and wind velocity
friction decreases effieciency but too slow also reduces efficiency. =
There could be this
relationship for oscillating magnetic field for extraction of power. I =
have done some
research on a faraday disk and it does hold true about the magnetic =
field rotation versus
velocity.... k*V^3 is frictional losses. =20

------=_NextPart_000_002B_01BE6D68.79D9DD20
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable

<!DOCTYPE HTML PUBLIC "-//W3C//DTD W3 HTML//EN">

Electrostatic implies that no power =is needed to=20sustain the field, when in fact there
are losses to keeping any high =potential in free=20space.  Now if one tries to use this
electrostatic energy for work, then =the field=20will start to either deplete or require more
current to sustain itself.  In =other=20words... the field is NOT free. 
 
What we should be looking at HARD, =is an energy=20supply that is NEVER depleted.
One that if we try to use the field =supply, it=20would allow us to use it without depleting.
Like an endless river supply.  =PERMENATE=20MAGNETICS!!  Free B-Field!!  This is
our key to endless energy, but we =have to get=20the static magnetic field to become
oscillatory.  If you can make a =magnetic=20field from a permenate magnetic oscillate
by either machanical means or field =modulation=20means, there would be your answer.
Now, this mechanical or field =modulation (FM)=20means would  also have to be free..
or at least the magnetic field =oscillations=20(integrate for power extraction) would have
to supply the oscillations=20means.  
 
Any takers for this kinda =project?  The=20TOMI is close..where magnetics are used to 
rotate a ball bearing.  If one =could=20produce that...ball bearing rotating continually..
I'd have to say.. you would be 75% =there to=20answers to free energy.
 
v/r Ken Carrigan
 
PS... it also could be that high =frequency=20oscillations are the answer vice slower or
lower oscillations.  Something =like a car..=20for gas milage?  Too fast and wind velocity
friction decreases effieciency but =too slow also=20reduces efficiency.  There could be this
relationship for oscillating =magnetic field for=20extraction of power.  I have done some
research on a faraday disk and it =does hold true=20about the magnetic field rotation versus
velocity.... k*V^3 is frictional =losses. =20
------=_NextPart_000_002B_01BE6D68.79D9DD20--